2n^2+20n+40=-10

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Solution for 2n^2+20n+40=-10 equation: 



2n^2+20n+40=-10

We move all terms to the left:

2n^2+20n+40-(-10)=0

We add all the numbers together, and all the variables

2n^2+20n+50=0

a = 2; b = 20; c = +50;
Δ = b2-4ac
Δ = 202-4·2·50
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$n=\frac{-b}{2a}=\frac{-20}{4}=-5$

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